OpenCV Python实现拼图小游戏

1. OpenCV Python实现拼图小游戏的介绍

拼图游戏是一种非常传统的游戏，因为其可玩性和创造性不断地受到人们的追捧。随着技术不断地进步，拼图游戏也发生了许多变化，其中之一就是 OpenCV Python实现拼图小游戏。此游戏是基于图像处理技术和Python 编程实现的。因此，本文将详细介绍 OpenCV Python实现拼图小游戏的步骤和技术。

2.拼图小游戏的实现过程

2.1 导入库和设置难度级别

OpenCV和 numpy等库是重要的库。我将使用OpenCV库中的 imread和imshow 函数来处理图像。同时， level_of_difficulty变量将被设置，以确定有多少个图块（pieces）需要进行拼图。

import cv2
import numpy as np
# 设置初级-拼图块为6 
level_of_difficulty = 6

2.2 读取原始图像，并根据难度级别将其分成若干份

读取原始图像，调整其大小，并确定块的大小。

#Load the image and get its dimension to calculate the block size
image = cv2.imread('image.png')
height, width = image.shape[:2]
# calculate the block size
block_size_w = int(width / np.sqrt(level_of_difficulty))
block_size_h = int(height / np.sqrt(level_of_difficulty))

根据 block_size_w和 block_size_h变量的值，将原始图像划分成若干块

# Store pieces here
pieces = []  
for i in range(0, height - block_size_h + 1, block_size_h):
    for j in range(0, width - block_size_w + 1, block_size_w):
        # Slice the image
        slice = image[i:i+block_size_h, j:j+block_size_w]
        pieces.append(slice)

2.3 调整图块的位置和写入文件

通过打乱块的顺序来调整块的位置。并将图块写入文件，以方便玩家玩游戏。

# Shuffle the pieces
np.random.shuffle(pieces)
#Create  a blank image just larger than original size 
mixed_image = np.zeros(image.shape, dtype=image.dtype)
#Iterate through to cut and merge using the shuffled pieces array
current_position = [0,0]
for index, piece in enumerate(pieces):
    upper_left = current_position
    
    if current_position[0] + block_size_h > height:
        current_position[0] = 0
        current_position[1] += block_size_w
    
    lower_right = current_position
    mixed_image[upper_left[0]:lower_right[0], upper_left[1]:lower_right[1]] = piece
    
    current_position[0] += block_size_h
# Save Image
cv2.imwrite('mixed_image.png', mixed_image)

2.4 创建一个简单的窗口，并捕获鼠标单击事件

在显示拼接后的图像之前，我们需要处理鼠标单击事件。因此，我们要在窗口中创建一段代码来执行这个任务。函数swap_positions将在每次单击鼠标时被调用。如果点击位置与正确的位置相同，则图块将被置换。

#Define mouse callback function
def swap_positions(event, x1, y1, flags, params):
    global pieces, mixed_image, block_size_h, block_size_w
    
    if event == cv2.EVENT_LBUTTONUP:
        #Identify row and column
        row = y1 // block_size_h
        col = x1 // block_size_w
        
        #Get piece index   
        piece_index = row * int(np.sqrt(len(pieces))) + col
        print('Piece index is: ', piece_index)
        
        # Get the locations of each piece
        piece_row_loc, piece_col_loc = np.where(pieces == piece_index)
        mixed_row_loc, mixed_col_loc = np.where(mixed_image == piece_index)
        
        if piece_index not in pieces_found:
            # Swap positions
            pieces[piece_row_loc[0]][piece_col_loc[0]] = mixed_image[mixed_row_loc[0]][mixed_col_loc[0]]
            mixed_image[mixed_row_loc[0]][mixed_col_loc[0]] = piece_index
            
            #Add to found list 
            pieces_found.append(piece_index)        
        
        # Rebuilding board
        current_position = [0,0]
        
        for index, piece in enumerate(pieces):
            upper_left = current_position
            
            if current_position[0] + block_size_h > height:
                current_position[0] = 0
                current_position[1] += block_size_w
            
            lower_right = current_position
            mixed_image[upper_left[0]:lower_right[0], upper_left[1]:lower_right[1]] = piece
            
            current_position[0] += block_size_h
        
        #If we have solved the puzzle
        if len(pieces_found) == len(pieces):
            print('Congratulations !')
        
        # Move piece into empty 
        cv2.imshow('Puzzle Image', mixed_image)

2.5 显示图像

通过以下代码行，显示拼接后的图像。还要更新位置并设置鼠标单击事件。

#Create window and display image
pieces_found = []
cv2.namedWindow('Puzzle Image')
cv2.imshow('Puzzle Image', mixed_image)
# Mouse Callback
cv2.setMouseCallback('Puzzle Image', swap_positions)
cv2.waitKey(0)
cv2.destroyAllWindows()

3. 结论

通过本文的介绍，我们可以看到 OpenCV Python实现拼图小游戏的过程和技术。总的来说，拼图小游戏是一项非常具有挑战性和创造性的工作。实现它需要基于图像处理技术的编程技能、创新思想和想象力。希望，这篇文章将能够帮助读者了解 OpenCV Python实现拼图小游戏，并进一步开拓他们的思路。