django xadmin action兼容自定义model权限教程

1. Introduction

Django xadmin is a powerful admin tool for Django, providing a user-friendly interface for managing and manipulating models within a Django project. In this tutorial, we will learn how to make actions compatible with custom model permissions in Django xadmin.

2. Overview of Django xadmin Actions

Django xadmin allows developers to define custom actions that can be performed on selected models or objects in the admin interface. These actions can be used to perform bulk operations on the selected items, such as deleting multiple objects or updating their attributes.

2.1 Defining Actions

To define an action in Django xadmin, we need to create a method in our admin class decorated with the @action decorator. This method should accept two arguments: self and queryset, where queryset is the selected models or objects.

from xadmin.actions import BaseActionView

class MyAction(BaseActionView):

action_name = "my_action"

description = "My Custom Action"

def do_action(self, queryset):

# Perform action here

3. Custom Model Permissions

In Django, we can define custom model permissions that control the access rights of users to perform specific actions on the models. These permissions can be added to the model's Meta class using the permissions attribute.

class MyModel(models.Model):

# Model fields and methods

class Meta:

permissions = [

("can_perform_action", "Can Perform Action"),

]

3.1 Assigning Permissions to Users

After defining custom model permissions, we need to assign them to specific users or user groups. This can be done through the Django admin interface or programmatically using Django's authentication framework.

from django.contrib.auth.models import User, Group

user = User.objects.get(username="user1")

user.user_permissions.add('myapp.can_perform_action')

group = Group.objects.get(name="group1")

group.permissions.add('myapp.can_perform_action')

4. Making Actions Compatible with Custom Model Permissions

To make actions compatible with custom model permissions in Django xadmin, we need to override the get_model_perm method in our admin class. This method should return a tuple containing the codename of the permission and the model name.

class MyModelAdmin(object):

# Other admin configurations

def get_model_perm(self, action):

return ('myapp.can_perform_action', self.model_name.lower())

Now, when the action is performed, Django xadmin will check if the current user has the required permission to perform the action. If the user doesn't have the permission, the action will be disabled in the admin interface.

5. Testing the Compatibility

To test the compatibility of our custom action with the custom model permission, we can create a new user or user group without the required permission and try to perform the action. If the action is disabled or an error message is displayed, then the compatibility is working as expected.

We can also use the has_permission method in our MyAction class to check if the current user has the required permission before performing the action.

class MyAction(BaseActionView):

# Other action configurations

def do_action(self, queryset):

if self.has_permission():

# Perform action here

else:

# Display error message

6. Conclusion

In this tutorial, we have learned how to make actions compatible with custom model permissions in Django xadmin. By overriding the get_model_perm method and assigning the required permissions to users or user groups, we can control the access rights of users to perform specific actions on models. This enhances the security and flexibility of the Django xadmin admin interface.

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